Before you begin
What you need: Fractions, reciprocals and LCM.
- Convert completion time into rate
- Combine constant work rates
- Solve staged-work problems
Understand the idea
One job is one whole
A person who finishes one job in 6 days completes 1/6 of it per day, assuming a constant rate. Completion time and rate are reciprocals.
Rates add when workers cooperate
If A and B work independently on the same divisible job without interference, their daily rates add. Their completion times do not.
Track the work already done
For changing teams, calculate work = rate × time in each stage. Subtract completed work from one, then divide the remaining work by the rate of the remaining team.
A 60-unit job makes rates visible
A method you can reuse
Together time = 1/(1/a + 1/b) = ab/(a + b)
For two positive solo times a and b, constant rates, and simultaneous independent work.- Choose one whole job or a convenient total number of work units.
- Find each worker's output per unit time.
- Add rates, then divide the remaining work by the combined rate.
The LCM of the solo times is a convenient number of total work units. It often turns fractional rates into integers.
Worked examples
Read the question first. Try a step yourself, then compare your reasoning.
Work together
A takes 12 days and B takes 20 days. Find their combined time.
- Use a 60-unit job.
- A does 5 units/day; B does 3 units/day.
- Time = 60/(5 + 3) = 7.5 days.
One worker leaves
A needs 6 days and B needs 12 days. They work together for 2 days, then A leaves. How much longer does B need?
- Combined daily rate = 1/6 + 1/12 = 1/4.
- Two days complete 1/2; 1/2 remains.
- B needs (1/2)/(1/12) = 6 more days.
Equal workers
Three identical workers finish in 8 days. How long would four need?
- The job takes 3 × 8 = 24 worker-days.
- Divide by four workers.
- Assume equal constant rates and unchanged conditions.
Check your understanding
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