Before you begin
What you need: Addition, division and simple equations.
- Find the arithmetic mean
- Recover missing values from a total
- Calculate a weighted combined average
Understand the idea
Average is an equal redistribution
The arithmetic mean is the value each item would have if the total were shared equally. The individual values may differ, but their sum is unchanged.
Keep track of total and count
The useful identity is total = average × count. If an item is added or removed, change both the total and the count before dividing.
Group sizes matter
A mean of two group averages is valid only when the groups have equal sizes. Otherwise, reconstruct the two totals and divide by the combined count.
Different values, the same fair share
A method you can reuse
Mean = sum of all values ÷ number of values
The count must be positive. Combined mean = (n₁m₁ + n₂m₂)/(n₁ + n₂).- Calculate or reconstruct the total.
- Adjust the total and count for additions, removals or replacements.
- Divide the updated total by the updated count and check the range.
Choose a convenient assumed mean. For 48, 51 and 54, use 50: deviations −2, +1, +4 sum to 3, so the mean is 50 + 3/3 = 51.
Worked examples
Read the question first. Try a step yourself, then compare your reasoning.
Find the mean
Average 12, 18, 24 and 30.
- Sum = 12 + 18 + 24 + 30 = 84.
- There are four values.
- 84 ÷ 4 = 21.
Remove a value
Eight values have mean 25. Remove the value 32. Find the new mean.
- Original total = 8 × 25 = 200.
- New total = 200 − 32 = 168; new count = 7.
- 168 ÷ 7 = 24.
Combine unequal groups
10 students average 60 marks; 20 students average 75. Find the combined mean.
- Group totals: 10 × 60 = 600 and 20 × 75 = 1500.
- Combined total = 2100; combined count = 30.
- 2100 ÷ 30 = 70.
Check your understanding
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